If p a 0.6 p b 0.2
WebSOLUTION: Given that P (A) = 0.6 and P (B) = 0.2, and P (A and B) = 0.12, determine P (B A). Algebra: Probability and statistics Solvers Lessons Answers archive Click here to … Web30 mrt. 2024 · If P (A) = 0.2 , P (B) = 0.4 and P (A U B) = 0.5, then value of P (A B) is Class 12 Solutions of Sample Papers and Past Year Papers - for Class 12 Boards CBSE Class …
If p a 0.6 p b 0.2
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WebA and B are mutually exclusive events. Select the correct answer using the code given below. Q5. Suppose P (A) = 0.4, P (B) = P and P (A ∪ B) = 0.7. If A and B are independent events, then the value of P is: Q6. A bag contains 5 black and 3 white balls. Two balls are drawn at random one after the other without replacement. WebPlay this game to review Probability. P(A) = 0.7 P(B) = 0.5 P(A∩B) = 0.2 Find P(A B)...
WebCorrect Answer: B. Explanation: (B) If A and B are mutually exclusive, P (A ∩ B) = 0. Thus 0.6 = 0.4 + P (B) - 0, and so P (B) = 0.2. If A and B are independent, then P (A ∩ B) = P … Web28 sep. 2024 · then A∩B' = {a,c} ∩ {a,d} = {a) and this leads to a contradiction because a cannot equal both 0.4 as well as 0.42 I WILL BE GLAD TO SEE ANALYSIS OF THIS FROM ANY INTERESTED TUTOR. Upvote • 0 Downvote
WebIf A, B, and C are mutually exclusive events with P (A) = 0.2, P (B) = 0.3, P (C) = 0.4, determine the following probabilities. a. P (A ∪ B ∪ C) b. P (A ∩ B ∩ C) c. P (A ∩ B) d. P [A ∪ B) ∩ C] e. P (A' ∩ B' ∩ C') economics Which of the following is least affected by an outlier? (mean, median, or range—pick one). probability Web22 okt. 2016 · P (A) = 1 - 0.2 = 0.8, and. P (B) = 1 - 0.4 = 0.6, so. P (A)P (B) = 0.8*0.6 = 0.48 = P (A ∩ B). Therefore, the events A and B are independent, by the definition of …
Web12 mrt. 2024 · 618 views 2 years ago. If P (A) = 0.6, P (B) = 0.5 and P (A B) = 0.3, then find P (A U B) class 12 math important questions Follow me on Instagram: …
WebIf A and B are independent events, such that P (A U B) = 0.7, P (B) = 0.5, then P (A) = …… A 0.2 B 0.6 C 0.4 D 0.3 Solution The correct option is C 0.4 Since, A and B are independent events, therefore P (A∩B) = P (A)P (B) Suggest Corrections 1 Similar questions Q. A and B are two events such that P (A)=0.5, P (A∪ ¯B)=0.7. emotional intelligence treeWeb13 nov. 2024 · So, you know P (A), P (B) and P (A or B) and you can solve for P A and B) => P (A and B) = P (A) + P (B) - P (A or B) P (A and B) = 0.5 + 0.3 - 0.6 = 0.8 - 0.6 = 0.2 Answer: P (A and B) = 0.2 Advertisement New questions in Mathematics Advertisement dramatized reading of matthew 27:45-46WebIf P(A)=0.2,P(B)=p,P(A∪B)=0.6 and A and B are given to be independent events, find the value of p. Medium Solution Verified by Toppr P (A)=0.2 P (B)=p P (AUB)=0.6 Since A and B are independent P (A ∩ B)=P (A) × P (B)=0.2p P (AUB)=P (A)+P (B)- P (A∩B) 0.6=0.2+p-0.2p p=0.5 Was this answer helpful? 0 0 Similar questions dramatizeme new story you tubeWeb18 mrt. 2015 · It follows that Pr ( A ∩ B) = 0. For the Pr ( A) = 1 case, you also need to modify the argument. Note that B is the disjoint union of A ∩ B and A c ∩ B. Because A … dramatized scenes from american historyWeb1 apr. 2024 · The value of P(AUB) = 0.72. Step-by-step explanation: As. P(A) = 0.6; P(B) = 0.3; P(A∩B) = 0.18; We can determine the value of P(A∩B) Using the formula. P(AUB) = … dramatized storiesWebP (A ∩ B) = 0.2 × 0.6 P (A ∩ B) = 0.12 We know that P (A ∪ B) = P (A) + P (B) - P (A ∩ B) Substituting the values P (A ∪ B) = 0.2 + 0.6 - 0.12 So we get P (A ∪ B) = 0.68 … emotional intelligence white paperWeb28 okt. 2024 · If P(A) = 0.3, P(B) = 0.2 and P(C) = 0.1 and A,B,C are independent events, find the probability of occurrence of at least one of the three events A, B and C. See answer Advertisement Advertisement srivarshini2006 srivarshini2006 Answer: probability is 0.2. because rhe probability of getting any one is. dramatized poetry